(9/x-3)+(6x/x^2-8x+15)=0

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Solution for (9/x-3)+(6x/x^2-8x+15)=0 equation:


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

9/x-(8*x)+(6*x)/(x^2)-3+15 = 0

9/x-8*x+(6*x)/(x^2)-3+15 = 0

15*x^-1-8*x^1+12*x^0 = 0

(12*x^1-8*x^2+15*x^0)/(x^1) = 0 // * x^2

x^1*(12*x^1-8*x^2+15*x^0) = 0

x^1

12*x-8*x^2+15 = 0

12*x-8*x^2+15 = 0

DELTA = 12^2-(-8*4*15)

DELTA = 624

DELTA > 0

x = (624^(1/2)-12)/(-8*2) or x = (-624^(1/2)-12)/(-8*2)

x = (4*39^(1/2)-12)/(-16) or x = (-4*39^(1/2)-12)/(-16)

x in { (4*39^(1/2)-12)/(-16), (-4*39^(1/2)-12)/(-16)}

x in { (4*39^(1/2)-12)/(-16), (-4*39^(1/2)-12)/(-16) }

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